Class 8 Maths Practical Geometry | Constructing a Quadrilateral |
Constructing a Quadrilateral
Given below are various ways through which a quadrilateral can be constructed.
Step No. |
Diagram |
Details |
1 |
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Create a triangle PQR based on SSS construction condition according to the lengths of the sides and of the diagonal. |
2 |
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Make an arc (Point S) which is at a given distance away from P. |
3 |
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Make an arc on the earlier arc on S which is at a given distance from point R. Name the intersection of the two points as S. |
4 |
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Join S with P and R. This will complete the quadrilateral PQRS. |
Problem: Construct a quadrilateral ABCD with following measurements.
AB = 4.5 cm, BC = 5.5 cm, CD = 4cm, AD = 6cm, AC = 7cm
Solution:
Step1: Draw Side BC = 5.5 cm and cut arcs above it from B (4.5 cm) and C (7 cm). Mark the intersection as A. Join AB and AC.
Step2: Draw and arc from A equal to 6 cm which is the length of AD.
Step3: Draw and arc from C equal to 4 cm which is the length of CD. Mark the intersection as D and join AD and CD.
2. When two diagonals and three sides are given.
Step No. |
Diagram |
Details |
1 |
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Create a triangle ACD based on SSS construction condition according to the lengths of the sides and of the diagonal. |
2 |
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Make an arc(with D as center) which is the length of the other diagonal. |
3 |
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Make an arc on the earlier arc which is at a given distance from point C (third side). Name the intersection of the two points as B. |
4 |
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Join B with A, C and D. This will complete the quadrilateral PQRS with the two diagonals. |
Problem: Construct a quadrilateral GOLD with following measurements.
OL = 7.5 cm, GL = 6 cm, GD = 6 cm, LD = 5 cm, OD = 10 cm
Solution:
Step1: Draw Side GD = 6 cm and cut arcs above it from G (6 cm) and D (5 cm). Mark the intersection as L. Join GL and DL
Step2: Draw and arc from L equal to 7.5 cm and from D equal to 10 cm which is the length of OL and OD resp
Step3: Mark the intersection as O and join OG, OL and OD.
When two adjacent sides and three angles are given.
Step No. |
Diagram |
Details |
1 |
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Draw one side and make an angle which is given. |
2 |
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Make another given angle from the newly formed side (X-axis). |
3 |
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Make another given angle. This would intersect with the Y axis formed above. The quadrilateral will be formed. |
Problem: Construct a quadrilateral PLAN with following measurements.
PL = 4 cm, LA = 6.5 cm, ∠P= 90°, ∠A = 110°, ∠N = 85°
Solution:
The sum of the angles of a quadrilateral is 360°. So, ∠P + ∠L + ∠A + ∠N = 360°.
90° + ∠L + 110° + 85° = 360°
∠L = 75°
Step1: Draw Side PL = 4 cm and draw an angle of 75° at point L. As vertex A is 6.5 cm away from L, cut a line segment LA of 6.5 cm from this ray.
Step2: Again draw an angle of 110° at point A.
Step3: draw an angle of 90° at point P. This ray will meet the previously drawn ray from A at point N.
When three sides and two included angles are given.
Step No. |
Diagram |
Details |
1 |
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Draw one side and make an angle which is given. |
2 |
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Make another given angle from the existing side (BC). |
3 |
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Mark the point on the new side (Y axis) at the point equal to the length of the given side. Mark it as D. |
4 |
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Join the points AD to form the fourth side of the quadrilateral. The quadrilateral is now complete. |
Problem: Construct a quadrilateral TRUE with following measurements.
TR = 3.5 cm, RU = 3 cm, UE = 4 cm, ∠R = 75°, ∠U = 120°
Solution:
Step1: Draw Side RU = 3 cm and an angle of 120° at point U. As vertex E is 4 cm away from U, cut a line segment UE of 4 cm from this ray.
Step2: Draw an angle of 75° at point R. As vertex T is 3.5 cm away from vertex R, cut a line segment RT of 3.5 cm from this ray.
Step3: Join T to E.
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